Class 11Chemistry8-3.Organic Chemistry : Purification and characterizationChemical analysis of organic compounds
MediumExplain the reason for the fusion of an organic compound with metallic sodium for testing nitrogen,sulphur,and halogens.
(N/A) Organic compounds contain elements like nitrogen,sulphur,and halogens in a covalent form.
These elements cannot be detected directly by standard chemical tests.
Fusion with metallic sodium converts these elements into their corresponding water-soluble ionic salts.
The reactions are as follows:
$Na + C + N \rightarrow NaCN$
$2Na + S \rightarrow Na_{2}S$
$Na + X \rightarrow NaX$ (where $X = Cl, Br, I$).
These ionic salts can then be easily detected using specific reagents.
These elements cannot be detected directly by standard chemical tests.
Fusion with metallic sodium converts these elements into their corresponding water-soluble ionic salts.
The reactions are as follows:
$Na + C + N \rightarrow NaCN$
$2Na + S \rightarrow Na_{2}S$
$Na + X \rightarrow NaX$ (where $X = Cl, Br, I$).
These ionic salts can then be easily detected using specific reagents.
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Similar Questions
Why is the test for nitrogen,sulphur,or halogens not carried out by the direct addition of reagents to an organic compound?
Easy
View SolutionWhich of the following compounds is not expected to show Lassaigne's test for nitrogen?
DifficultJEE MAIN 2013
View SolutionThe Lassaigne's extract is boiled with dilute $HNO_3$ before testing for halogens because,
DifficultAIIMS 2012
View SolutionMatch the List-$I$ with List-$II$:
List-$I$ (Reagent) List-$II$ (Functional Group detected) $A$. Sodium bicarbonate solution $I$. Double bond/unsaturation $B$. Neutral ferric chloride $II$. Carboxylic acid $C$. Ceric ammonium nitrate $III$. Phenolic $-OH$ $D$. Alkaline $KMnO_4$ $IV$. Alcoholic $-OH$
Choose the correct answer from the options given below:
| List-$I$ (Reagent) | List-$II$ (Functional Group detected) |
| $A$. Sodium bicarbonate solution | $I$. Double bond/unsaturation |
| $B$. Neutral ferric chloride | $II$. Carboxylic acid |
| $C$. Ceric ammonium nitrate | $III$. Phenolic $-OH$ |
| $D$. Alkaline $KMnO_4$ | $IV$. Alcoholic $-OH$ |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2025
View SolutionConsider the following table$-$
Column-$I$
Column-$II$
$A$. Best and latest technique for isolation,purification and separation of organic compounds
$i$. Chromatography
$B$. In Lassaigne's test for $N$
$ii$. Vacuum distillation
$C$. In Lassaigne's test for $S$
$iii$. Violet coloured complex is formed
$D$. Aniline is separated from water by
$iv$. Prussian blue coloured complex is formed
$E$. Glycerol is purified from spent lye
$v$. Steam distillation
The correct match is$-$
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. Best and latest technique for isolation,purification and separation of organic compounds | $i$. Chromatography |
| $B$. In Lassaigne's test for $N$ | $ii$. Vacuum distillation |
| $C$. In Lassaigne's test for $S$ | $iii$. Violet coloured complex is formed |
| $D$. Aniline is separated from water by | $iv$. Prussian blue coloured complex is formed |
| $E$. Glycerol is purified from spent lye | $v$. Steam distillation |
The correct match is$-$
Medium
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