Factorise x^{2}+9 y^{2}+4+6 x y+12 y+4 x. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We use the algebraic identity: $(a+b+c)^{2} = a^{2}+b^{2}+c^{2}+2ab+2bc+2ca$.Given expression: $x^{2}+9 y^{2}+4+6 x y+12 y+4 x$.We can rewrite thi

Vedclass · Accepted Answer

$(x+3y+2)^{2}$

Vedclass · Answer

(A) We use the algebraic identity: $(a+b+c)^{2} = a^{2}+b^{2}+c^{2}+2ab+2bc+2ca$.Given expression: $x^{2}+9 y^{2}+4+6 x y+12 y+4 x$.We can rewrite this as:$= (x)^{2} + (3y)^{2} + (2)^{2} + 2(x)(3y) + 2(3y)(2) + 2(2)(x)$.Comparing this with the identity,where $a=x$,$b=3y$,and $c=2$,we get:$= (x+3y+2)^{2}$.Thus,the factors are $(x+3y+2)(x+3y+2)$.

Factorise $x^{2}+9 y^{2}+4+6 x y+12 y+4 x$.

Similar Questions

Show that $p-1$ is a factor of $p^{10}-1$ and also of $p^{11}-1$.

Find $p(1)$,$p(2)$,and $p(4)$ for the polynomial $p(x) = x^{3} - 7x^{2} + 14x - 8$.

Find the following product:
$\left(\frac{x}{2}+2 y\right)\left(\frac{x^{2}}{4}-x y+4 y^{2}\right)$

Determine which of the following polynomials has $(x-2)$ as a factor:
$A) 3x^2 + 6x - 24$
$B) 4x^2 + x - 2$

Expand $(x+2t)(x-5t)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module