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(A) The velocity of a wave is given by the formula $v = \lambda f$.From the given graph,the distance between two consecutive crests or two consecutive

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$1.0$

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(A) The velocity of a wave is given by the formula $v = \lambda f$.From the given graph,the distance between two consecutive crests or two consecutive troughs represents the wavelength $\lambda$.The graph shows that one full wave cycle (from $0.1 \ cm$ to $0.5 \ cm$) corresponds to a distance of $0.4 \ cm$.Thus,the wavelength $\lambda = 0.4 \ cm = 0.4 	imes 10^{-2} \ m = 4 	imes 10^{-3} \ m$.The frequency $f$ is given as $250 \ Hz$.Substituting these values into the formula:$v = (4 	imes 10^{-3} \ m) 	imes (250 \ Hz)$$v = 1000 	imes 10^{-3} \ m/s$$v = 1.0 \ m/s$.

The figure shows the shape of a part of a long string in which transverse waves are produced by attaching one end of the string to a tuning fork of frequency $250 \ Hz$. What is the velocity of the waves in $ms^{-1}$?

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