The displacement of a particle in a medium is $y = 10^{-4} \sin(100t + 20x + \frac{\pi}{3}) \ m$,where $t$ is in seconds and $x$ is in metres. The speed of the wave is (in $m/s$)

The equation of a progressive wave is given by $y = 6 \cos(100t - 4x)$ where $y$ is in $\mu\text{m}$, $x$ is in metre and $t$ is in second. The ratio of the maximum particle velocity to the velocity of wave is

The figure shows the wave $y = A \sin(\omega t - kx)$. What is the magnitude of the slope of the curve at $B$?

For a wave equation $y = 10 \sin \pi (0.01x - 2.00t) \text{ cm}$,what is the maximum particle velocity in $\text{cm/sec}$?

If a given wave has a propagation constant of $\frac{5 \pi}{7} \, rad/m$,then the phase difference between two particles having a distance difference of $\frac{49}{22} \, m$ is ..... $rad.$ (Take $\pi = \frac{22}{7}$)

The amplitude of a wave represented by the displacement equation $y = \frac{1}{\sqrt{a}} \sin \omega t \pm \frac{1}{\sqrt{b}} \cos \omega t$ will be