The figure shows a bar magnet and a long stra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic field produced by the long straight wire $W$ at any point on the magnet is given by the right-hand rule. Since the current is into th

Vedclass · Accepted Answer

The magnet experiences a force along the line of shortest distance.

Vedclass · Answer

(D) The magnetic field produced by the long straight wire $W$ at any point on the magnet is given by the right-hand rule. Since the current is into the plane of the paper,the magnetic field lines are concentric circles around the wire.Because the point $P$ is the midpoint of the bar magnet,the magnetic field produced by the wire at the North pole $(N)$ and the South pole $(S)$ of the magnet will be symmetric with respect to the line of shortest distance.The force on the North pole $(F_N = mB_N)$ and the force on the South pole $(F_S = mB_S)$ will have equal magnitudes and opposite directions relative to the axis of the magnet,but their components along the line of shortest distance will be in the same direction.Since the magnetic field is symmetric about the line of shortest distance passing through the midpoint $P$,the net torque on the magnet about its center $P$ is zero.However,the net force on the magnet will be directed along the line of shortest distance towards or away from the wire,depending on the orientation of the magnet's poles.

Similar Questions

$A$ short bar magnet is placed in a uniform magnetic field of $2 \ T$ such that the axis of the magnet makes an angle of $45^{\circ}$ with the direction of the magnetic field. If the torque acting on the magnet is $0.36 \sqrt{2} \ Nm$,then the magnetic moment of the magnet is: (in $J \ T^{-1}$)

$A$ small bar magnet placed with its axis at $30^{\circ}$ with an external field of $0.06\, T$ experiences a torque of $0.018\, Nm$. The minimum work required to rotate it from its stable to unstable equilibrium position is

Two identical dipoles each of magnetic moment $1.0 \, A-m^2$ are placed at a separation of $2 \, m$ with their axes perpendicular to each other. What is the magnetic field at a point midway between the dipoles?

Vedclass Test Series

Exam Paper Generator

Online Exam Module