A magnetic dipole of magnetic moment 6 times | vedclass

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(C) Given: Magnetic moment $ M = 6 	imes 10^{-2} 	ext{ A m}^2 $, Moment of inertia $ I = 12 	imes 10^{-6} 	ext{ kg m}^2 $, Magnetic field $ B = 2

Vedclass · Accepted Answer

$12$

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(C) Given: Magnetic moment $ M = 6 	imes 10^{-2} 	ext{ A m}^2 $, Moment of inertia $ I = 12 	imes 10^{-6} 	ext{ kg m}^2 $, Magnetic field $ B = 2 	imes 10^{-2} 	ext{ T} $.The time period $ t $ of a magnetic dipole oscillating in a magnetic field is given by $ t = 2 \pi \sqrt{\frac{I}{MB}} $.Substituting the values: $ t = 2 \pi \sqrt{\frac{12 	imes 10^{-6}}{(6 	imes 10^{-2}) 	imes (2 	imes 10^{-2})}} $.$ t = 2 \pi \sqrt{\frac{12 	imes 10^{-6}}{12 	imes 10^{-4}}} = 2 \pi \sqrt{10^{-2}} = 2 \pi 	imes 10^{-1} 	ext{ s} $.Given $ \pi \simeq 3 $, so $ t = 2 	imes 3 	imes 0.1 = 0.6 	ext{ s} $.The time taken to complete $ 20 $ oscillations is $ T = 20 	imes t = 20 	imes 0.6 = 12 	ext{ s} $.

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