The figure shows electric field lines due to a charge configuration. From this,we conclude that:

  • A
    $q_1$ and $q_2$ are positive and $q_2 > q_1$
  • B
    $q_1$ and $q_2$ are positive and $q_1 > q_2$
  • C
    $q_1$ and $q_2$ are negative and $|q_1| > |q_2|$
  • D
    $q_1$ and $q_2$ are negative and $|q_2| > |q_1|$

Explore More

Similar Questions

The electric field in a region of space is given by $\overrightarrow E = E_0 \hat i + 2E_0 \hat j$,where $E_0 = 100 \, N/C$. The flux of the field through a circular surface of radius $0.02 \, m$ parallel to the $Y-Z$ plane is nearly:

Five charges $+q, +5q, -2q, +3q$ and $-4q$ are situated as shown in the figure. The electric flux due to this configuration through the surface $S$ is

Why do two electric field lines not intersect each other?

Consider an electric field $\vec{E} = E_0 \hat{i}$,where $E_0$ is a constant. The flux through the shaded area (as shown in the figure) due to this field is

$A$ point charge $+q$ is placed at the centre of a cube of side $L$. The electric flux emerging from the cube is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo