Five charges +q, +5q, -2q, +3q and -4q are si | vedclass

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(B) According to Gauss's law,the electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{	ext{in}}}{\epsilon_0}$,where $q_{	ext{i

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$\frac{4q}{\epsilon_0}$

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(B) According to Gauss's law,the electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{	ext{in}}}{\epsilon_0}$,where $q_{	ext{in}}$ is the net charge enclosed by the surface.From the figure,the charges enclosed by the surface $S$ are $+q, +5q,$ and $-2q$.The charges $+3q$ and $-4q$ are outside the surface $S$,so they do not contribute to the electric flux through the surface.Therefore,the net enclosed charge is $q_{	ext{in}} = (+q) + (+5q) + (-2q) = 4q$.Substituting this into Gauss's law,we get $\phi = \frac{4q}{\epsilon_0}$.

Five charges $+q, +5q, -2q, +3q$ and $-4q$ are situated as shown in the figure. The electric flux due to this configuration through the surface $S$ is

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