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(B) According to Gauss's law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{Q_{en}}{\epsilon_0}$,where $Q_{en}$ is

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equal to the total flux through $S$ due to charges $q_3$ and $q_4$

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(B) According to Gauss's law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{Q_{en}}{\epsilon_0}$,where $Q_{en}$ is the net charge enclosed by the surface.In the given figure,only the charges $q_3$ and $q_4$ are enclosed by the closed surface $S$.Therefore,the net charge enclosed by the surface is $Q_{en} = q_3 + q_4$.Substituting this into Gauss's law,the total flux through the surface $S$ is $\phi = \frac{q_3 + q_4}{\epsilon_0}$.This flux depends only on the charges inside the surface ($q_3$ and $q_4$) and is independent of the charges outside the surface ($q_1$ and $q_2$).Thus,the total flux through $S$ is equal to the flux due to charges $q_3$ and $q_4$.

The figure shows four charges $q_1, q_2, q_3$ and $q_4$ fixed in space. The total flux of the electric field through a closed surface $S$,due to all charges $q_1, q_2, q_3$ and $q_4$ is:

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