Find $p(0)$,$p(1)$,and $p(2)$ for the following polynomial: $p(t) = 2 + t + 2t^2 - t^3$.

(N/A) Given the polynomial: $p(t) = 2 + t + 2t^2 - t^3$.
To find $p(0)$,substitute $t = 0$ into the polynomial:
$p(0) = 2 + (0) + 2(0)^2 - (0)^3 = 2 + 0 + 0 - 0 = 2$.
To find $p(1)$,substitute $t = 1$ into the polynomial:
$p(1) = 2 + (1) + 2(1)^2 - (1)^3 = 2 + 1 + 2(1) - 1 = 2 + 1 + 2 - 1 = 4$.
To find $p(2)$,substitute $t = 2$ into the polynomial:
$p(2) = 2 + (2) + 2(2)^2 - (2)^3 = 2 + 2 + 2(4) - 8 = 2 + 2 + 8 - 8 = 4$.