Find $p(1)$,$p(2)$,and $p(4)$ for the following polynomial: $p(y) = y^{2} - 5y + 4$.
(N/A) To find the values of the polynomial $p(y) = y^{2} - 5y + 4$ at given points,we substitute the value of $y$ into the expression:
$1$. For $y = 1$: $p(1) = (1)^{2} - 5(1) + 4 = 1 - 5 + 4 = 0$.
$2$. For $y = 2$: $p(2) = (2)^{2} - 5(2) + 4 = 4 - 10 + 4 = -2$.
$3$. For $y = 4$: $p(4) = (4)^{2} - 5(4) + 4 = 16 - 20 + 4 = 0$.
Thus,the values are $p(1) = 0$,$p(2) = -2$,and $p(4) = 0$.
$1$. For $y = 1$: $p(1) = (1)^{2} - 5(1) + 4 = 1 - 5 + 4 = 0$.
$2$. For $y = 2$: $p(2) = (2)^{2} - 5(2) + 4 = 4 - 10 + 4 = -2$.
$3$. For $y = 4$: $p(4) = (4)^{2} - 5(4) + 4 = 16 - 20 + 4 = 0$.
Thus,the values are $p(1) = 0$,$p(2) = -2$,and $p(4) = 0$.
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