Find $p(1)$,$p(2)$,and $p(4)$ for the following polynomial: $p(t) = t^{2} - 6t + 8$.
(N/A) To find the values,substitute the given values of $t$ into the polynomial $p(t) = t^{2} - 6t + 8$.
For $t = 1$: $p(1) = (1)^{2} - 6(1) + 8 = 1 - 6 + 8 = 3$.
For $t = 2$: $p(2) = (2)^{2} - 6(2) + 8 = 4 - 12 + 8 = 0$.
For $t = 4$: $p(4) = (4)^{2} - 6(4) + 8 = 16 - 24 + 8 = 0$.
For $t = 1$: $p(1) = (1)^{2} - 6(1) + 8 = 1 - 6 + 8 = 3$.
For $t = 2$: $p(2) = (2)^{2} - 6(2) + 8 = 4 - 12 + 8 = 0$.
For $t = 4$: $p(4) = (4)^{2} - 6(4) + 8 = 16 - 24 + 8 = 0$.
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