Find frac{dy}{dx},if x = 2 cos theta - cos 2 | vedclass

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(A) Given,$x = 2 \cos 	heta - \cos 2 	heta$ and $y = 2 \sin 	heta - \sin 2 	heta$. Differentiating with respect to $	heta$: $\frac{dx}{d	heta} =

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$	an \frac{3 	heta}{2}$

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(A) Given,$x = 2 \cos 	heta - \cos 2 	heta$ and $y = 2 \sin 	heta - \sin 2 	heta$. Differentiating with respect to $	heta$: $\frac{dx}{d	heta} = -2 \sin 	heta + 2 \sin 2 	heta = 2(\sin 2 	heta - \sin 	heta)$. $\frac{dy}{d	heta} = 2 \cos 	heta - 2 \cos 2 	heta = 2(\cos 	heta - \cos 2 	heta)$. Now,$\frac{dy}{dx} = \frac{dy/d	heta}{dx/d	heta} = \frac{2(\cos 	heta - \cos 2 	heta)}{2(\sin 2 	heta - \sin 	heta)} = \frac{\cos 	heta - \cos 2 	heta}{\sin 2 	heta - \sin 	heta}$. Using trigonometric identities $\cos C - \cos D = -2 \sin \frac{C+D}{2} \sin \frac{C-D}{2}$ and $\sin C - \sin D = 2 \cos \frac{C+D}{2} \sin \frac{C-D}{2}$: $\frac{dy}{dx} = \frac{-2 \sin \frac{3 	heta}{2} \sin \frac{-	heta}{2}}{2 \cos \frac{3 	heta}{2} \sin \frac{	heta}{2}} = \frac{2 \sin \frac{3 	heta}{2} \sin \frac{	heta}{2}}{2 \cos \frac{3 	heta}{2} \sin \frac{	heta}{2}} = 	an \frac{3 	heta}{2}$.

Find $\frac{dy}{dx}$,if $x = 2 \cos \theta - \cos 2 \theta$ and $y = 2 \sin \theta - \sin 2 \theta$.

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