Find the curved and total surface area of a c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Radius $(r) = 6\, cm$,Height $(h) = 8\, cm$.First,calculate the slant height $(l)$ using the formula $l = \sqrt{r^2 + h^2}$.$l = \sqrt{6^2

Vedclass · Accepted Answer

$60\, \pi,\, 96\, \pi$

Vedclass · Answer

(A) Given: Radius $(r) = 6\, cm$,Height $(h) = 8\, cm$.First,calculate the slant height $(l)$ using the formula $l = \sqrt{r^2 + h^2}$.$l = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10\, cm$.Now,calculate the curved surface area $(CSA) = \pi r l$.$CSA = \pi 	imes 6 	imes 10 = 60\pi\, cm^2$.Next,calculate the total surface area $(TSA) = \pi r l + \pi r^2$.$TSA = 60\pi + \pi(6)^2 = 60\pi + 36\pi = 96\pi\, cm^2$.Thus,the curved surface area is $60\pi\, cm^2$ and the total surface area is $96\pi\, cm^2$.

Find the curved and total surface area of a conical flask of radius $6\, cm$ and height $8\, cm$.

Similar Questions

The area of a triangle is $216 \, cm^{2}$ and its sides are in the ratio $3:4:5$. The perimeter of the triangle is ....... $cm$.

An isosceles right-angled triangle has an area of $200 \, cm^2$. The length of its hypotenuse is ..... $cm$.

If the ratio of the areas of two squares is $9: 1$,then the ratio of their perimeters is

$A$ field is in the shape of a parallelogram. Its adjacent sides and one diagonal are $65 \, m$,$119 \, m$,and $156 \, m$ respectively. Find the cost of gravelling it at the rate of $₹ 10$ per $m^2$ (in $Rs.$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module