If the ratio of the areas of two squares is 9 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the sides of the two squares be $x$ and $y$ respectively.The area of a square is given by the formula $	ext{Area} = 	ext{side}^2$.Given the

Vedclass · Accepted Answer

$3: 1$

Vedclass · Answer

(C) Let the sides of the two squares be $x$ and $y$ respectively.The area of a square is given by the formula $	ext{Area} = 	ext{side}^2$.Given the ratio of the areas is $\frac{x^2}{y^2} = \frac{9}{1}$.Taking the square root of both sides,we get $\frac{x}{y} = \sqrt{\frac{9}{1}} = \frac{3}{1}$.The perimeter of a square is given by the formula $	ext{Perimeter} = 4 	imes 	ext{side}$.The ratio of their perimeters is $\frac{4x}{4y} = \frac{x}{y}$.Substituting the value of $\frac{x}{y}$,the ratio of the perimeters is $3: 1$.

If the ratio of the areas of two squares is $9: 1$,then the ratio of their perimeters is

Similar Questions

$A$ $2 \text{ m}$ broad pathway is to be constructed around a rectangular plot on the inside. The area of the plot is $96 \text{ m}^2$. The rate of construction is $₹ 50 / \text{ m}^2$. Find the total cost of construction (in $₹$).

The number of revolutions a wheel of diameter $40 \, cm$ makes in travelling a distance of $176 \, m$ is:

The area of a rectangle is $460 \, m^2$. If the length is $15 \%$ more than the breadth,what is the breadth of the rectangular field? (in $metres$)

In a right-angled triangle,find the hypotenuse if the base and perpendicular are respectively $36015 \ cm$ and $48020 \ cm$.

$A$ parallelogram has sides $60\, cm$ and $40\, cm$ and one of its diagonals is $80\, cm$ long. Its area is

Vedclass Test Series

Exam Paper Generator

Online Exam Module