Find the odd number from the given sequence: | vedclass

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Question

(B) The given sequence is $8, 27, 64, 125, 216$.These numbers can be written as cubes of consecutive integers:$8 = 2^3$$27 = 3^3$$64 = 4^3$$125 = 5^3$

Vedclass · Accepted Answer

$64$

Vedclass · Answer

(B) The given sequence is $8, 27, 64, 125, 216$.These numbers can be written as cubes of consecutive integers:$8 = 2^3$$27 = 3^3$$64 = 4^3$$125 = 5^3$$216 = 6^3$Upon closer inspection,all these numbers are perfect cubes. However,in many aptitude contexts,the question asks for an 'odd' number based on a specific property. If we look at the parity,$8, 64, 216$ are even,while $27, 125$ are odd. If we look at the sequence $2^3, 3^3, 4^3, 5^3, 6^3$,there is no obvious 'odd' one out by value. However,if the question implies identifying a number that does not fit a pattern,there might be an error in the premise. Given the options,if we consider parity,$27$ and $125$ are odd,while $8, 64, 216$ are even. Since there is no single odd number,this question is likely flawed. Assuming the intended logic was to find a number that is not a cube,all are cubes. If we must choose,$64$ is the only one that is also a perfect square $(8^2)$. Thus,$64$ is the most distinct.

Find the odd number from the given sequence: $8, 27, 64, 125, 216$.

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