Find product V in the following reaction sequ | vedclass

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(D) The reaction sequence is as follows:$1.$ Reduction: $CH_3-CH(CH_3)-COOH \xrightarrow{LiAlH_4/H_3O^{+}} CH_3-CH(CH_3)-CH_2OH$ $(I)$$2.$ Bromination

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$CH_3-CH(CH_3)-CH_2-COOH$

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(D) The reaction sequence is as follows:$1.$ Reduction: $CH_3-CH(CH_3)-COOH \xrightarrow{LiAlH_4/H_3O^{+}} CH_3-CH(CH_3)-CH_2OH$ $(I)$$2.$ Bromination: $CH_3-CH(CH_3)-CH_2OH \xrightarrow{PBr_3} CH_3-CH(CH_3)-CH_2Br$ $(II)$$3.$ Grignard formation: $CH_3-CH(CH_3)-CH_2Br \xrightarrow{Mg/ether} CH_3-CH(CH_3)-CH_2MgBr$ $(III)$$4.$ Carboxylation: $CH_3-CH(CH_3)-CH_2MgBr \xrightarrow{CO_2} CH_3-CH(CH_3)-CH_2COOMgBr$ $(IV)$$5.$ Hydrolysis: $CH_3-CH(CH_3)-CH_2COOMgBr \xrightarrow{H_3O^{+}} CH_3-CH(CH_3)-CH_2COOH$ $(V)$The final product $V$ is $3$-methylbutanoic acid.

Find product $V$ in the following reaction sequence:
$CH_3-CH(CH_3)-COOH$ $\xrightarrow[H_3O^{+}]{LiAlH_4} I$ $\xrightarrow{PBr_3} II$ $\xrightarrow[ether]{Mg} III$ $\xrightarrow{CO_2} IV$ $\xrightarrow{H_3O^{+}} V$

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Find product $V$ in the following reaction sequence:$CH_3-CH(CH_3)-COOH$ $\xrightarrow[H_3O^{+}]{LiAlH_4} I$ $\xrightarrow{PBr_3} II$ $\xrightarrow[ether]{Mg} III$ $\xrightarrow{CO_2} IV$ $\xrightarrow{H_3O^{+}} V$