(B) The given $A.P.$ is $18, 16.5, 15, 13.5, \ldots$Here,the first term $a = 18$.The common difference $d = 16.5 - 18 = -1.5$.The formula for the $n^{

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(B) The given $A.P.$ is $18, 16.5, 15, 13.5, \ldots$Here,the first term $a = 18$.The common difference $d = 16.5 - 18 = -1.5$.The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.Substituting the values,we get:$T_n = 18 + (n - 1)(-1.5)$$T_n = 18 - 1.5n + 1.5$$T_n = -1.5n + 19.5$.

Class 10 Mathematics Arithmetic Progressions Mix Examples - Arithmetic Progressions

Easy

Find the $n^{th}$ term of the $A.P. \, 18, 16.5, 15, 13.5, \ldots$

A
$1.5n + 16.5$
B
$-1.5n + 19.5$
C
$1.5n + 19.5$
D
$-1.5n + 16.5$

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Class 10

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Arithmetic Progressions

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Mix Examples - Arithmetic Progressions

Find the $12^{th}$ term and the $24^{th}$ term of the $A.P.$ $9, 13, 17, \ldots$

Medium

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For the finite $A.P.$ $5, 9, 13, \ldots, 101$,find the $9^{th}$ term from the end.

Easy

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The sum of the first $n$ odd natural numbers is:

Medium

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For a given $A.P.$,$S_{n} = 5n^{2} + 8n$. Hence $T_{n} = \ldots \ldots \ldots \ldots$

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The sum of three numbers in $A.P.$ is $21$. The product of the first and the third number exceeds the second number by $6$. Find those numbers.

Medium

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Find the $n^{th}$ term of the $A.P. \, 18, 16.5, 15, 13.5, \ldots$

Similar Questions

Find the $12^{th}$ term and the $24^{th}$ term of the $A.P.$ $9, 13, 17, \ldots$

For the finite $A.P.$ $5, 9, 13, \ldots, 101$,find the $9^{th}$ term from the end.

The sum of the first $n$ odd natural numbers is:

For a given $A.P.$,$S_{n} = 5n^{2} + 8n$. Hence $T_{n} = \ldots \ldots \ldots \ldots$

The sum of three numbers in $A.P.$ is $21$. The product of the first and the third number exceeds the second number by $6$. Find those numbers.

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