Find the derivative of $f(x) = \frac{x+1}{x}$.

  • A
    $1 - \frac{1}{x^2}$
  • B
    $-\frac{1}{x^2}$
  • C
    $\frac{1}{x^2}$
  • D
    $1 + \frac{1}{x^2}$

Explore More

Similar Questions

Let $f(x + y) = f(x)f(y)$ and $f(x) = 1 + \sin(3x)g(x)$,where $g(x)$ is continuous. Then $f'(x)$ is:

If $f(x) = 4x^3 + 3x^2 + 3x + 4$,$x \neq 0$,then $\frac{d}{dx}\left(x^3 \cdot f\left(\frac{1}{x}\right)\right) =$ . . . . . .

If $y = \log x \cdot e^{(\tan x + x^2)}$,then $\frac{dy}{dx} = $

The derivative of $e^{ax} \cos bx$ with respect to $x$ is $re^{ax} \cos(bx + \alpha)$,where $\alpha = \tan^{-1}(\frac{b}{a})$. When $a > 0, b > 0$,the value of $r$ is:

If $f(x) = 2x^6 + 3x^4 + 4x^2$,then $f'(x)$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo