Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $x^{2} + x - 3 = 0$

(A) For the quadratic equation $ax^{2} + bx + c = 0$,the discriminant $D$ is given by $D = b^{2} - 4ac$.
Comparing $x^{2} + x - 3 = 0$ with the standard form,we have $a = 1, b = 1, c = -3$.
Substituting these values into the formula:
$D = (1)^{2} - 4(1)(-3)$
$D = 1 + 12 = 13$.
Since $D > 0$,the roots of the equation are real and distinct.