(D) For an orbital,the principal quantum number $n$ represents the shell,and the azimuthal quantum number $l$ represents the subshell. Given $n=4$ and

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(D) For an orbital,the principal quantum number $n$ represents the shell,and the azimuthal quantum number $l$ represents the subshell. Given $n=4$ and $l=1$. Since $l=1$ corresponds to the $p$ subshell,the orbital is $4p$. Comparing with the options: $4s \rightarrow n=4, l=0$ $3d \rightarrow n=3, l=2$ $4d \rightarrow n=4, l=2$ $4p \rightarrow n=4, l=1$ Therefore,the correct option is $D$.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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Find the exact orbital from the following for which $n=4$ and $l=1$.

AP EAMCET 2020 All AP EAMCET

A
$4 s$
B
$3 d$
C
$4 d$
D
$4 p$

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Structure of Atom

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Quantum number, Electronic configuration and Shape of orbitals

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Find the exact orbital from the following for which $n=4$ and $l=1$.

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What is the number of radial nodes in the $2s$ orbital?

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Which of the following pairs of ions have the same electronic configuration?

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Which of the following set of quantum numbers is correct for the $19^{th}$ electron of chromium?
$n$ $l$ $m$ $s$

Statement $A$: An orbital can accommodate a maximum of two electrons.
Reason $R$: Two electrons in an orbital produce opposite magnetic fields.