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(B) The greatest number of $4$ digits is $9999$.Dividing $9999$ by $196$,we get $9999 = 196 	imes 51 + 3$. The remainder is $3$.Thus,the greatest $4$

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$9996, 10192$

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(B) The greatest number of $4$ digits is $9999$.Dividing $9999$ by $196$,we get $9999 = 196 	imes 51 + 3$. The remainder is $3$.Thus,the greatest $4$-digit number divisible by $196$ is $9999 - 3 = 9996$.The least number of $5$ digits is $10000$.Dividing $10000$ by $196$,we get $10000 = 196 	imes 51 + 4$. The remainder is $4$.To find the least $5$-digit number divisible by $196$,we add $(196 - 4)$ to $10000$.Thus,the required $5$-digit number is $10000 + (196 - 4) = 10000 + 192 = 10192$.

Find the greatest number of $4$ digits and the least number of $5$ digits that have $196$ as their $HCF$.

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