Find the greatest number of five digits which | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) First,find the $L.C.M.$ of the divisors $4, 6, 10,$ and $15$.Prime factorization: $4 = 2^2, 6 = 2 	imes 3, 10 = 2 	imes 5, 15 = 3 	imes 5$.$L.C

Vedclass · Accepted Answer

$99963$

Vedclass · Answer

(D) First,find the $L.C.M.$ of the divisors $4, 6, 10,$ and $15$.Prime factorization: $4 = 2^2, 6 = 2 	imes 3, 10 = 2 	imes 5, 15 = 3 	imes 5$.$L.C.M. = 2^2 	imes 3 	imes 5 = 4 	imes 3 	imes 5 = 60$.The greatest five-digit number is $99999$.Divide $99999$ by $60$ to find the remainder: $99999 \div 60 = 1666$ with a remainder of $39$.Subtract the remainder from the greatest five-digit number to find the largest number divisible by $60$: $99999 - 39 = 99960$.To leave a remainder of $3$ in each case,add $3$ to this number: $99960 + 3 = 99963$.

Find the greatest number of five digits which when divided by $4, 6, 10$ and $15$ leaves the same remainder $3$ in each case.

Similar Questions

$A$ room is $4\, m\, 37\, cm$ long and $3\, m\, 23\, cm$ broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose.

The least number of square tiles required to cover the ceiling of a room $15\, m\, 17\, cm$ long and $9\, m\, 2\, cm$ broad is:

The $LCM$ of two prime numbers $x$ and $y$ $(x > y)$ is $161$. The value of $3y - x$ is

Find the greatest number which will divide $25, 73$ and $97$ so as to leave the same remainder in each case.

The $L.C.M.$ and $G.C.D.$ of two numbers are $1530$ and $51,$ respectively. Find how many such pairs are possible?

Vedclass Test Series

Exam Paper Generator

Online Exam Module