Find the mean and the median of the observati | vedclass

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(A) Step $1$: To find the mean, sum all the observations and divide by the total number of observations.Sum $= 72 + 15 + 28 + 31 + 32 + 51 + 44 + 43 +

Vedclass · Accepted Answer

Mean $= 42, 	ext{Median} = 43$

Vedclass · Answer

(A) Step $1$: To find the mean, sum all the observations and divide by the total number of observations.Sum $= 72 + 15 + 28 + 31 + 32 + 51 + 44 + 43 + 62 = 378$.Total number of observations $(n) = 9$.Mean $= \frac{378}{9} = 42$.Step $2$: To find the median, arrange the observations in ascending order.Ordered data: $15, 28, 31, 32, 43, 44, 51, 62, 72$.Since $n = 9$ (which is odd), the median is the value at the $\frac{n+1}{2}$-th position.Median $= \frac{9+1}{2} = 5	ext{-th position}$.The $5	ext{-th}$ value in the ordered list is $43$.Therefore, Mean $= 42$ and Median $= 43$.

Class interval $(km/h)$	Frequency
$30-40$	$3$
$40-50$	$6$
$50-60$	$25$
$60-70$	$65$
$70-80$	$50$
$80-90$	$28$
$90-100$	$14$

Length (in mm)	Number of leaves
$118-126$	$8$
$127-135$	$10$
$136-144$	$12$
$145-153$	$17$
$154-162$	$7$
$163-171$	$5$
$172-180$	$3$

Find the mean and the median of the observations: $72, 15, 28, 31, 32, 51, 44, 43$ and $62$.

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