The following table shows a frequency distribution for the speed of cars passing through a particular spot on a highway:

Class interval $(km/h)$	Frequency
$30-40$	$3$
$40-50$	$6$
$50-60$	$25$
$60-70$	$65$
$70-80$	$50$
$80-90$	$28$
$90-100$	$14$

Draw the frequency polygon representing the above data without drawing the histogram.

(N/A) To draw the frequency polygon without a histogram,we first calculate the class marks (mid-points) for each interval.

Class interval $(km/h)$	Class marks	Frequency
$30-40$	$35$	$3$
$40-50$	$45$	$6$
$50-60$	$55$	$25$
$60-70$	$65$	$65$
$70-80$	$75$	$50$
$80-90$	$85$	$28$
$90-100$	$95$	$14$

$1$. Plot the points $(35, 3), (45, 6), (55, 25), (65, 65), (75, 50), (85, 28),$ and $(95, 14)$ on a graph paper.
$2$. To close the polygon,include two additional class intervals with zero frequency: $20-30$ (mid-point $25$) and $100-110$ (mid-point $105$).
$3$. Join the points $(25, 0), (35, 3), (45, 6), (55, 25), (65, 65), (75, 50), (85, 28), (95, 14),$ and $(105, 0)$ with line segments to obtain the frequency polygon.