Find the mean deviation about the mean for th | vedclass

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(A) Step $1$: Calculate the mean of the given data:$\bar{x} = \frac{6+7+10+12+13+4+8+12}{8} = \frac{72}{8} = 9$Step $2$: Find the absolute deviations

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$2.75$

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(A) Step $1$: Calculate the mean of the given data:$\bar{x} = \frac{6+7+10+12+13+4+8+12}{8} = \frac{72}{8} = 9$Step $2$: Find the absolute deviations of the observations from the mean $|x_i - \bar{x}|$:$|6-9| = 3$$|7-9| = 2$$|10-9| = 1$$|12-9| = 3$$|13-9| = 4$$|4-9| = 5$$|8-9| = 1$$|12-9| = 3$Step $3$: Calculate the mean deviation about the mean:$M.D.(\bar{x}) = \frac{\sum |x_i - \bar{x}|}{n} = \frac{3+2+1+3+4+5+1+3}{8} = \frac{22}{8} = 2.75$

Class interval	$0-6$	$6-12$	$12-18$	$18-24$	$24-30$
Frequency	$4$	$5$	$3$	$6$	$2$

Find the mean deviation about the mean for the following data:
$6, 7, 10, 12, 13, 4, 8, 12$

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Find the mean deviation about the mean for the following data:$6, 7, 10, 12, 13, 4, 8, 12$