Find the mean of the following frequency dist | vedclass

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(B) To find the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)$: $1

Vedclass · Accepted Answer

$41$

Vedclass · Answer

(B) To find the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)$: $15, 25, 35, 45, 55, 65$.$2$. Calculate $f_i x_i$:$2 	imes 15 = 30$$10 	imes 25 = 250$$40 	imes 35 = 1400$$25 	imes 45 = 1125$$13 	imes 55 = 715$$10 	imes 65 = 650$$3$. Sum of frequencies $(\sum f_i)$: $2 + 10 + 40 + 25 + 13 + 10 = 100$.$4$. Sum of products $(\sum f_i x_i)$: $30 + 250 + 1400 + 1125 + 715 + 650 = 4170$.$5$. Mean $(\bar{x})$: $\frac{4170}{100} = 41.7$.

Class	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$
Frequency	$2$	$10$	$40$	$25$	$13$	$10$

Height (in $cm$)	Number of students
$150-155$	$15$
$155-160$	$13$
$160-165$	$10$
$165-170$	$8$
$170-175$	$9$
$175-180$	$5$

Find the mean of the following frequency distribution:

Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$

Frequency $2$ $10$ $40$ $25$ $13$ $10$

(in $.7$)

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Find the mean of the following frequency distribution: Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ Frequency $2$ $10$ $40$ $25$ $13$ $10$ (in $.7$)