Consider the following frequency distribution | vedclass

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(C) $1$. Modal Class: The modal class is the class interval with the highest frequency. Here,the highest frequency is $15$,which corresponds to the cl

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$315$

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(C) $1$. Modal Class: The modal class is the class interval with the highest frequency. Here,the highest frequency is $15$,which corresponds to the class interval $150-155$. Thus,the lower limit of the modal class is $150$.$2$. Median Class: To find the median class,we calculate the cumulative frequency $(cf)$:- $150-155$: $cf = 15$- $155-160$: $cf = 15 + 13 = 28$- $160-165$: $cf = 28 + 10 = 38$- $165-170$: $cf = 38 + 8 = 46$- $170-175$: $cf = 46 + 9 = 55$- $175-180$: $cf = 55 + 5 = 60$The total number of students $N = 60$. So,$N/2 = 30$. The cumulative frequency just greater than $30$ is $38$,which corresponds to the class interval $160-165$. Thus,the upper limit of the median class is $165$.$3$. Final Calculation: The sum of the lower limit of the modal class $(150)$ and the upper limit of the median class $(165)$ is $150 + 165 = 315$.

Marks	Number of students
Below $10$	$10$
Below $20$	$50$
Below $30$	$130$
Below $40$	$270$
Below $50$	$440$
Below $60$	$570$
Below $70$	$670$
Below $80$	$740$
Below $90$	$780$
Below $100$	$800$

Class	Frequency $(f)$
$110-120$	$6$
$120-130$	$25$
$130-140$	$48$
$140-150$	$72$
$150-160$	$116$
$160-170$	$60$
$170-180$	$38$
$180-190$	$22$
$190-200$	$3$

Class	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$3$	$x$	$7$	$7$	$y$

Similar Questions

In the usual notations,$Z - M = \ldots \ldots \ldots \quad (M - \bar{x})$

Find the median of the following frequency distribution:

Class Frequency $(f)$

$110-120$ $6$

$120-130$ $25$

$130-140$ $48$

$140-150$ $72$

$150-160$ $116$

$160-170$ $60$

$170-180$ $38$

$180-190$ $22$

$190-200$ $3$

For a given frequency distribution,the total frequency is $25$ and $\Sigma f_{i} x_{i} = 120$. Then,the mean is $\ldots$

The mean of the following data is $55.5$ and the total frequency is $20$. Find the missing frequencies $x$ and $y$.
Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
Frequency $3$ $x$ $7$ $7$ $y$

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Height (in $cm$)	Number of students
$150-155$	$15$
$155-160$	$13$
$160-165$	$10$
$165-170$	$8$
$170-175$	$9$
$175-180$	$5$

Consider the following frequency distribution of the heights of $60$ students of a class: Height (in $cm$) Number of students $150-155$ $15$ $155-160$ $13$ $160-165$ $10$ $165-170$ $8$ $170-175$ $9$ $175-180$ $5$ The sum of the lower limit of the modal class and upper limit of the median class is: