Find the mean of the following frequency dist | vedclass

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(C) To find the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)$: $5

Vedclass · Accepted Answer

$47.2$

Vedclass · Answer

(C) To find the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)$: $5, 15, 25, 35, 45, 55, 65, 75$.$2$. Calculate $f_i x_i$: $2 	imes 5 = 10$$4 	imes 15 = 60$$10 	imes 25 = 250$$20 	imes 35 = 700$$18 	imes 45 = 810$$20 	imes 55 = 1100$$16 	imes 65 = 1040$$10 	imes 75 = 750$$3$. Sum of frequencies $(\sum f_i)$ = $2 + 4 + 10 + 20 + 18 + 20 + 16 + 10 = 100$.$4$. Sum of $f_i x_i$ $(\sum f_i x_i)$ = $10 + 60 + 250 + 700 + 810 + 1100 + 1040 + 750 = 4720$.$5$. Mean $\bar{x} = \frac{4720}{100} = 47.2$.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$2$	$4$	$10$	$20$	$18$	$20$	$16$	$10$

Find the mean of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

Frequency $2$ $4$ $10$ $20$ $18$ $20$ $16$ $10$

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Find the mean of the following frequency distribution: Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $2$ $4$ $10$ $20$ $18$ $20$ $16$ $10$