The formula to find the mean of an ungrouped data is ........
- A$\bar{x}=\Sigma x_{i}$
- B$\bar{x}=\frac{\Sigma x_{i}}{n}$
- C$\bar{x}=\frac{\Sigma x_{i}}{2}$
- D$\bar{x}=n \cdot \Sigma x_{i}$
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Similar Questions
Calculate the mean of the following frequency distribution:
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ Frequency $12$ $16$ $8$ $6$ $8$
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ |
| Frequency | $12$ | $16$ | $8$ | $6$ | $8$ |
Medium
View SolutionFor the calculation of mode of the following frequency distribution,$f_{1} = \dots \dots \dots \dots \dots \dots$
Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$ Frequency $12$ $18$ $27$ $20$ $17$ $6$
| Class | $0-100$ | $100-200$ | $200-300$ | $300-400$ | $400-500$ | $500-600$ |
| Frequency | $12$ | $18$ | $27$ | $20$ | $17$ | $6$ |
Easy
View SolutionFind the mean,median and mode of the following frequency distribution:
Class $0-50$ $50-100$ $100-150$ $150-200$ $200-250$ $250-300$ $300-350$ Frequency $10$ $15$ $30$ $20$ $15$ $8$ $2$
| Class | $0-50$ | $50-100$ | $100-150$ | $150-200$ | $200-250$ | $250-300$ | $300-350$ |
| Frequency | $10$ | $15$ | $30$ | $20$ | $15$ | $8$ | $2$ |
Medium
View SolutionWill the median class and modal class of grouped data always be different? Justify your answer.
Easy
View SolutionIn the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{2} = \ldots \ldots \ldots$
Easy
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