In the formula Z = l + left( frac{f_{1} - f_{ | vedclass

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(D) In the formula for calculating the mode of grouped data,the variables are defined as follows:$Z$ is the mode.$l$ is the lower limit of the modal c

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frequency of the class succeeding the modal class

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(D) In the formula for calculating the mode of grouped data,the variables are defined as follows:$Z$ is the mode.$l$ is the lower limit of the modal class.$f_{1}$ is the frequency of the modal class.$f_{0}$ is the frequency of the class preceding the modal class.$f_{2}$ is the frequency of the class succeeding the modal class.$c$ is the size of the class interval.Therefore,$f_{2}$ represents the frequency of the class succeeding the modal class.

Class	$0-15$	$15-30$	$30-45$	$45-60$	$60-75$	$75-90$	$90-105$
Frequency	$4$	$5$	$23$	$45$	$66$	$42$	$15$

Class	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$	$90-100$
Frequency	$5$	$7$	$12$	$10$	$8$	$6$	$2$

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{2} = \ldots \ldots \ldots$

Similar Questions

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$l = \ldots \ldots \ldots$

Find the mode of the following frequency distribution:

Class $0-15$ $15-30$ $30-45$ $45-60$ $60-75$ $75-90$ $90-105$

Frequency $4$ $5$ $23$ $45$ $66$ $42$ $15$

For a given frequency distribution,$\bar{x}=54.3, \Sigma f_{i} u_{i}=2, n=25$ and $c=10$. Then the assumed mean $A = \dots$

Find the mean,median and mode of the following frequency distribution:

Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$ $90-100$

Frequency $5$ $7$ $12$ $10$ $8$ $6$ $2$

If $x_{i}$ are the midpoints of the class intervals of grouped data,$f_{i}$ are the corresponding frequencies,and $\bar{x}$ is the mean,then $\sum (f_{i} x_{i} - f_{i} \bar{x})$ is equal to

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