For the calculation of mode of the following frequency distribution,$f_{1} = \dots \dots \dots \dots \dots \dots$
Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$ Frequency $12$ $18$ $27$ $20$ $17$ $6$
| Class | $0-100$ | $100-200$ | $200-300$ | $300-400$ | $400-500$ | $500-600$ |
| Frequency | $12$ | $18$ | $27$ | $20$ | $17$ | $6$ |
- A$18$
- B$20$
- C$27$
- D$17$
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Similar Questions
The formula to find the mean of an ungrouped data is ........
Easy
View SolutionThe following are the ages of $300$ patients getting medical treatment in a hospital on a particular day:
Age (in years) $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ Number of patients $60$ $42$ $55$ $70$ $53$ $20$
Form:
$(i)$ Less than type cumulative frequency distribution.
$(ii)$ More than type cumulative frequency distribution.
| Age (in years) | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ |
| Number of patients | $60$ | $42$ | $55$ | $70$ | $53$ | $20$ |
Form:
$(i)$ Less than type cumulative frequency distribution.
$(ii)$ More than type cumulative frequency distribution.
Medium
View SolutionIn the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$,$u_{i} =$ .........
Easy
View SolutionIn the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$f_{0} = \ldots \ldots \ldots$
Easy
View SolutionThe mean of $15$ observations is $25$. Later on,it was found that one observation was taken by mistake as $20$ instead of $50$. Then,the correct mean is:
Medium
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