The following are the ages of $300$ patients getting medical treatment in a hospital on a particular day:
Age (in years) $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$
Number of patients $60$ $42$ $55$ $70$ $53$ $20$

Form:
$(i)$ Less than type cumulative frequency distribution.
$(ii)$ More than type cumulative frequency distribution.

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(N/A) $(i)$ To form a 'less than' type cumulative frequency distribution,we add the frequencies of all classes preceding the current class. Since the data starts from $10-20$,we assume $0$ patients are less than $10$ years old.
$(ii)$ To form a 'more than' type cumulative frequency distribution,we start with the total number of patients $(300)$ and subtract the frequency of each preceding class interval.
Age (in years) Less than type (Cumulative Frequency) Age (in years) More than type (Cumulative Frequency)
Less than $10$ $0$ $10$ or more $300$
Less than $20$ $60$ $20$ or more $240$
Less than $30$ $102$ $30$ or more $198$
Less than $40$ $157$ $40$ or more $143$
Less than $50$ $227$ $50$ or more $73$
Less than $60$ $280$ $60$ or more $20$
Less than $70$ $300$ $70$ or more $0$

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Similar Questions

The mean of the following frequency distribution is $46$. Find the missing frequency $f$.
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Frequency $10, f, 7, 6, 5, 4$

If $x_{i}$ are the midpoints of the class intervals of grouped data,$f_{i}$ are the corresponding frequencies,and $\bar{x}$ is the mean,then $\sum (f_{i} x_{i} - f_{i} \bar{x})$ is equal to

Consider the following frequency distribution of the heights of $60$ students of a class:
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$150-155$ $15$
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$160-165$ $10$
$165-170$ $8$
$170-175$ $9$
$175-180$ $5$

The sum of the lower limit of the modal class and upper limit of the median class is:

Find the mean of the distribution:
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Frequency $9$ $22$ $27$ $17$

For a given frequency distribution,$A=325, c=50, \Sigma f_{i} u_{i}=28$ and $\Sigma f_{i}=200$. Then,mean $\bar{x}=\ldots \ldots \ldots . .$

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