Find the number of monochlorinated products f | vedclass

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(B) The structure of $2$-methylbutane is $CH_3-CH(CH_3)-CH_2-CH_3$. To find the number of monochlorinated structural isomers,we replace each unique hy

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The structure of $2$-methylbutane is $CH_3-CH(CH_3)-CH_2-CH_3$. To find the number of monochlorinated structural isomers,we replace each unique hydrogen atom with a chlorine atom: $1$. Replacing a hydrogen on the terminal $CH_3$ group (attached to $CH$) gives $1$-chloro-$2$-methylbutane: $CH_2Cl-CH(CH_3)-CH_2-CH_3$. $2$. Replacing the hydrogen on the $CH$ group gives $2$-chloro-$2$-methylbutane: $CH_3-CCl(CH_3)-CH_2-CH_3$. $3$. Replacing a hydrogen on the $CH_2$ group gives $2$-methyl-$3$-chlorobutane: $CH_3-CH(CH_3)-CHCl-CH_3$. $4$. Replacing a hydrogen on the terminal $CH_3$ group (attached to $CH_2$) gives $1$-chloro-$3$-methylbutane: $CH_3-CH(CH_3)-CH_2-CH_2Cl$. Thus,there are $4$ distinct structural isomers formed.

Find the number of monochlorinated products formed by $2$-methylbutane. $(\text{Only structural isomers})$

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