Find the radian measure corresponding to the | vedclass

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Question

(A) We know that $1^{\circ} = 60^{\prime}$,so $30^{\prime} = (\frac{30}{60})^{\circ} = 0.5^{\circ}$.Thus,$-47^{\circ} 30^{\prime} = -(47 + 0.5)^{\circ

Vedclass · Accepted Answer

$-\frac{19}{72} \pi$

Vedclass · Answer

(A) We know that $1^{\circ} = 60^{\prime}$,so $30^{\prime} = (\frac{30}{60})^{\circ} = 0.5^{\circ}$.Thus,$-47^{\circ} 30^{\prime} = -(47 + 0.5)^{\circ} = -47.5^{\circ} = -\frac{95}{2}^{\circ}$.Since $180^{\circ} = \pi 	ext{ radians}$,$1^{\circ} = \frac{\pi}{180} 	ext{ radians}$.Therefore,$-\frac{95}{2}^{\circ} = (-\frac{95}{2}) 	imes \frac{\pi}{180} 	ext{ radians}$.Simplifying the expression: $(-\frac{95}{360}) \pi = -\frac{19}{72} \pi 	ext{ radians}$.Hence,$-47^{\circ} 30^{\prime} = -\frac{19}{72} \pi 	ext{ radians}$.

Find the radian measure corresponding to the following degree measure: $-47^{\circ} 30^{\prime}$.

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