Find the sum of an AP of 40 terms whose first | vedclass

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(C) The sum of an $AP$ is given by the formula $S_n = \frac{n}{2}(a_1 + a_n)$,where $n$ is the number of terms,$a_1$ is the first term,and $a_n$ is th

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$7100$

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(C) The sum of an $AP$ is given by the formula $S_n = \frac{n}{2}(a_1 + a_n)$,where $n$ is the number of terms,$a_1$ is the first term,and $a_n$ is the last term.Given:Number of terms $n = 40$First term $a_1 = 80$Last term $a_{40} = 275$Substituting these values into the formula:$S_{40} = \frac{40}{2}(80 + 275)$$S_{40} = 20(355)$$S_{40} = 7100$Thus,the sum of the $40$ terms is $7100$.

Find the sum of an $AP$ of $40$ terms whose first and last terms are $80$ and $275$.

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