Find the unit digit in the product (4387)^{24 | vedclass

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(D) To find the unit digit of $(4387)^{245} 	imes (621)^{72}$,we focus on the unit digits of the bases.$1$. For $(4387)^{245}$,the unit digit is the

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$7$

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(D) To find the unit digit of $(4387)^{245} 	imes (621)^{72}$,we focus on the unit digits of the bases.$1$. For $(4387)^{245}$,the unit digit is the same as $7^{245}$. The powers of $7$ follow a cycle of $4$: $7^1 = 7$,$7^2 = 9$,$7^3 = 3$,$7^4 = 1$. $2$. Divide the exponent $245$ by $4$: $245 = 4 	imes 61 + 1$. The remainder is $1$. Thus,the unit digit of $(4387)^{245}$ is $7^1 = 7$.$3$. For $(621)^{72}$,any power of a number ending in $1$ will always have a unit digit of $1$. Thus,the unit digit of $(621)^{72}$ is $1$.$4$. The unit digit of the product is the product of the unit digits: $7 	imes 1 = 7$.

Find the unit digit in the product $(4387)^{245} \times (621)^{72}$.

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