Find the value of x, y and z from the followi | vedclass

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(A) Given the matrix equation: $\begin{bmatrix} x+y+z \ x+z \ y+z \end{bmatrix} = \begin{bmatrix} 9 \ 5 \ 7 \end{bmatrix}$Since the two matrices a

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$x=2, y=4, z=3$

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(A) Given the matrix equation: $\begin{bmatrix} x+y+z \ x+z \ y+z \end{bmatrix} = \begin{bmatrix} 9 \ 5 \ 7 \end{bmatrix}$Since the two matrices are equal,their corresponding elements must be equal. Comparing the corresponding elements,we get:$x+y+z = 9$  $(1)$$x+z = 5$  $(2)$$y+z = 7$  $(3)$Substituting equation $(2)$ into equation $(1)$:$y + (x+z) = 9$$y + 5 = 9 \Rightarrow y = 4$Now,substitute $y=4$ into equation $(3)$:$4 + z = 7 \Rightarrow z = 3$Finally,substitute $z=3$ into equation $(2)$:$x + 3 = 5 \Rightarrow x = 2$Thus,the values are $x=2, y=4, z=3$.

Find the value of $x, y$ and $z$ from the following equation: $\begin{bmatrix} x+y+z \\ x+z \\ y+z \end{bmatrix} = \begin{bmatrix} 9 \\ 5 \\ 7 \end{bmatrix}$

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