Find the value of frac{1.53 times 0.9995}{1.5 | vedclass

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(C) Step $1$: Perform the multiplication $1.53 	imes 0.9995 = 1.529235$. Step $2$: According to the rules of significant figures,the result of multip

Vedclass · Accepted Answer

$0.961$

Vedclass · Answer

(C) Step $1$: Perform the multiplication $1.53 	imes 0.9995 = 1.529235$. Step $2$: According to the rules of significant figures,the result of multiplication should have the same number of significant figures as the measurement with the fewest significant figures. Here,$1.53$ has $3$ significant figures and $0.9995$ has $4$. Thus,the product should be rounded to $3$ significant figures: $1.53$. Step $3$: Perform the division $\frac{1.53}{1.592} = 0.961055...$. Step $4$: The result of division should also be rounded to the least number of significant figures present in the operands. Here,$1.53$ has $3$ significant figures and $1.592$ has $4$. Therefore,the final result must be rounded to $3$ significant figures,which is $0.961$.

List-$I$ (Number)	List-$II$ (Significant figures)
$A. 1001$	$I. 3$
$B. 010.1$	$II. 4$
$C. 100.100$	$III. 5$
$D. 0.0010010$	$IV. 6$

Find the value of $\frac{1.53 \times 0.9995}{1.592}$ with due regard for significant figures.

Similar Questions

The length,breadth,and thickness of a block are given by $l = 12 \, cm$,$b = 6 \, cm$,and $t = 2.45 \, cm$. The volume of the block according to the rules of significant figures should be:

What is a significant number? What is a significant digit?

Match List-$I$ with List-$II$.

List-$I$ (Number) List-$II$ (Significant figures)

$A. 1001$ $I. 3$

$B. 010.1$ $II. 4$

$C. 100.100$ $III. 5$

$D. 0.0010010$ $IV. 6$

Choose the correct answer from the options given below:

$Assertion$ : The number of significant figures depends on the least count of the measuring instrument.
$Reason$ : Significant figures define the accuracy of the measuring instrument.

What points should be considered during the multiplication and division of numbers with significant figures?

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