Find the value of $x$ and $y$ in the following nuclear reaction:
${}_{92}^{235} U + {}_{0}^{1} n \rightarrow {}_{x}^{133} Sb + {}_{41}^{y} Nb + 4 {}_{0}^{1} n$

The power obtained in a reactor using $^{235}U$ disintegration is $1000 \text{ kW}$. The mass decay of $^{235}U$ per hour is ............ $\mu g$.

If $200 \, MeV$ energy is released in the fission of a single ${U^{235}}$ nucleus, the number of fissions required per second to produce $1 \, kW$ power shall be (Given $1 \, eV = 1.6 \times 10^{-19} \, J$)

Nuclear fission was discovered by

Nuclear fission is best explained by
[$AIPMT$ $2000$]

The number of neutrons released when ${}_{92}^{235}U$ undergoes fission by absorbing ${}_{0}^{1}n$ and products ${}_{56}^{144}Ba$ and ${}_{36}^{89}Kr$ are formed,is: