Find the value of $\sqrt[5]{(243)^{-3}}$.

Rationalise the denominator of the following expression and evaluate it by taking $\sqrt{2}=1.414, \sqrt{3}=1.732$,and $\sqrt{5}=2.236$ up to three decimal places:
$\frac{\sqrt{2}}{2+\sqrt{2}}$

Simplify the following:
$3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$

Fill in the blank to make the following statement true:
$\sqrt[11]{1} = \ldots$

Simplify: $\left(1^{3}+2^{3}+3^{3}\right)^{\frac{1}{2}}$

Express the following in the form $\frac{p}{q},$ where $p$ and $q$ are integers and $q \neq 0$ :
$0.00323232 \ldots$