Find the voltage V_2 across R_2 for the given | vedclass

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Question

(D) Let the potential at the central node be $V$. Applying Kirchhoff's Current Law $(KCL)$ at this node:$\frac{V - 12}{8} + \frac{V}{2} + \frac{V - 6}

Vedclass · Accepted Answer

$3.43$

Vedclass · Answer

(D) Let the potential at the central node be $V$. Applying Kirchhoff's Current Law $(KCL)$ at this node:$\frac{V - 12}{8} + \frac{V}{2} + \frac{V - 6}{2 + 2} = 0$Multiplying the entire equation by $8$ to clear the denominators:$(V - 12) + 4V + 2(V - 6) = 0$$V - 12 + 4V + 2V - 12 = 0$$7V - 24 = 0$$7V = 24$$V = \frac{24}{7} \approx 3.43 \ V$Since $R_2$ is connected between this node and ground,the voltage across $R_2$ is $V_2 = V = 3.43 \ V$.

Find the voltage $V_2$ across $R_2$ for the given circuit. (in $V$)

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