Find the zeroes of the quadratic polynomial $x^{2}+7x+10$,and verify the relationship between the zeroes and the coefficients.

(N/A) We have the quadratic polynomial $p(x) = x^{2}+7x+10$.
To find the zeroes,we set $p(x) = 0$:
$x^{2}+7x+10 = 0$
$x^{2}+5x+2x+10 = 0$
$x(x+5)+2(x+5) = 0$
$(x+2)(x+5) = 0$
Thus,the zeroes are $x = -2$ and $x = -5$.
Verification:
Sum of zeroes $= (-2) + (-5) = -7 = \frac{-7}{1} = \frac{-(\text{Coefficient of } x)}{\text{Coefficient of } x^{2}}$.
Product of zeroes $= (-2) \times (-5) = 10 = \frac{10}{1} = \frac{\text{Constant term}}{\text{Coefficient of } x^{2}}$.
Hence,the relationship is verified.