Find the total number of electrons,protons,an | vedclass

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(B) $1$. Calculate the number of moles of $_{16}^{32}S$: $	ext{Moles} = \frac{	ext{mass}}{	ext{molar mass}} = \frac{0.192 \ g}{32 \ g/mol} = 0.006

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$1.734 	imes 10^{23}$

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(B) $1$. Calculate the number of moles of $_{16}^{32}S$: $	ext{Moles} = \frac{	ext{mass}}{	ext{molar mass}} = \frac{0.192 \ g}{32 \ g/mol} = 0.006 \ mol$. $2$. Calculate the number of atoms: $	ext{Atoms} = 0.006 	imes 6.022 	imes 10^{23} = 3.6132 	imes 10^{21} 	ext{ atoms}$. $3$. For $_{16}^{32}S$,the number of protons = $16$,electrons = $16$,and neutrons = $32 - 16 = 16$. $4$. Total subatomic particles per atom = $16 + 16 + 16 = 48$. $5$. Total number of particles = $3.6132 	imes 10^{21} 	imes 48 = 1.734 	imes 10^{23}$.

Find the total number of electrons,protons,and neutrons in $0.192 \ g$ of $_{16}^{32}S$.

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