Following compounds are given: (i) CH_3-CH_2- | vedclass

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(C) The iodoform test is given by compounds containing either a methyl keto group $(CH_3-CO-)$ or a methyl hydroxy group $(CH_3-CH(OH)-)$ which can be

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$(i), (ii)$ and $(iii)$

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(C) The iodoform test is given by compounds containing either a methyl keto group $(CH_3-CO-)$ or a methyl hydroxy group $(CH_3-CH(OH)-)$ which can be oxidized to a methyl keto group. $(i) CH_3-CH_2-OH$ (Ethanol) oxidizes to $CH_3-CHO$,which gives the iodoform test. $(ii) CH_3-CO-CH_3$ (Acetone) contains the $CH_3-CO-$ group. $(iii) CH_3-CH(OH)-CH_3$ (Propan$-2-$ol) oxidizes to $CH_3-CO-CH_3$. $(iv) CH_3-OH$ (Methanol) does not contain the required group. Therefore,$(i), (ii),$ and $(iii)$ will give a positive iodoform test.

Following compounds are given:
$(i) CH_3-CH_2-OH$
$(ii) CH_3-CO-CH_3$
$(iii) CH_3-CH(OH)-CH_3$
$(iv) CH_3-OH$
Which of the above compound$(s)$,on being warmed with iodine solution and $NaOH$,will give iodoform?

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Following compounds are given: $(i) CH_3-CH_2-OH$ $(ii) CH_3-CO-CH_3$ $(iii) CH_3-CH(OH)-CH_3$ $(iv) CH_3-OH$ Which of the above compound$(s)$,on being warmed with iodine solution and $NaOH$,will give iodoform?