For $0 < \theta < 90^{\circ},$ the value of $\ldots \ldots \ldots \ldots$ increases as $\theta$ increases from $0^{\circ}$ to $90^{\circ}$.

  • A
    $\cos \theta$
  • B
    $\sin \theta$
  • C
    $\operatorname{cosec} \theta$
  • D
    $\cot \theta$

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In $\Delta ABC$, $AC = 5$, $BC = 13$, $m \angle A = 90^\circ$, then $\tan B = \ldots$

In $\Delta ABC$,$m \angle C = 90^{\circ}$ and $\cos B = \frac{1}{2}$,then $\operatorname{cosec} A = \ldots$

$\frac{\sec \theta-1}{\sec \theta+1} = \ldots$

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