For A(0, 0) and B(4, 8),M is the midpoint of | vedclass

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(B) The midpoint formula for two points $(x_1, y_1)$ and $(x_2, y_2)$ is $\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$.First,find the coordinate

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$(3, 6)$

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(B) The midpoint formula for two points $(x_1, y_1)$ and $(x_2, y_2)$ is $\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$.First,find the coordinates of $M$,which is the midpoint of $\overline{AB}$ where $A(0, 0)$ and $B(4, 8)$:$M = \left(\frac{0+4}{2}, \frac{0+8}{2}\right) = (2, 4)$.Next,find the coordinates of $N$,which is the midpoint of $\overline{BM}$ where $B(4, 8)$ and $M(2, 4)$:$N = \left(\frac{4+2}{2}, \frac{8+4}{2}\right) = \left(\frac{6}{2}, \frac{12}{2}\right) = (3, 6)$.

For $A(0, 0)$ and $B(4, 8)$,$M$ is the midpoint of $\overline{AB}$ and $N$ is the midpoint of $\overline{BM}$,then the coordinates of $N$ are.........

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