For $x>1$,if $(2x)^{2y} = 4e^{2x-2y}$,then $(1+\log 2x)^2 \frac{dy}{dx}$ is equal to

  • A
    $\frac{\log 2x + \log 2}{x}$
  • B
    $\frac{x \log 2x - \log 2}{x}$
  • C
    $\frac{x \log 2x + \log 2}{x}$
  • D
    $\frac{\log 2x - \log 2}{x}$

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