For $a \neq 0$ and $b \neq 0$,if the real valued function $f(x) = \frac{\sqrt[5]{a(625+x)} - 5}{\sqrt[4]{625+bx} - 5}$ is continuous at $x = 0$,then $f(0) =$

  • A
    $\frac{4a}{5b}$
  • B
    $\frac{5a}{4b}$
  • C
    $\frac{5}{4b}$
  • D
    $\frac{4}{5b}$

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