For a $CE$ amplifier,current gain is $69$. If the emitter current is $7\, mA$,then the base current and collector current will be:

For a common-emitter transistor amplifier, the current gain is $60$. If the emitter current is $6.6 \,mA$, then its base current is (in $\,mA$)

In the circuit shown in the figure,the input voltage $V_i$ is $20\, V$,$V_{BE} = 0$,and $V_{CE} = 0$. The values of $I_B$,$I_C$,and $\beta$ are given by:

$A$ common emitter circuit is used as an amplifier with a current gain of $50$. If the input resistance is $1 \ k\Omega$ and the input voltage is $5 \ V$, then the output current is ....... $mA$.

$A$ $n-p-n$ transistor is connected in common-emitter configuration in which the collector supply is $8\, V$ and the voltage drop across the load resistance of $800\,\Omega$ connected in the collector circuit is $0.8\, V$. If the current amplification factor $\alpha$ is $25/26$,the collector-emitter voltage $V_{CE}$ and the base current $I_B$ will be:

When an $n-p-n$ junction transistor is used as an amplifier in common emitter mode,